Question

The dissociation energy of H, is 430.53 KJ/mole. IfH,
is exposed to radiant energy of wavelength 253.7 nm,
what % of radiant energy will be converted into K.E.​

Answer 1

Energy required to break H-H bond

=430.53×1036.023×1023 J/Molecules

=7.15×10−19 J

Energy of photon used for this purpose = hcλ

=6.625×10−34×3.0×108253.7×10−9

=7.83×10−19 J

Energy left = (7.83−7.15)×10−19

Energy converted into K.E = 0.68×10−19 J

% of energy used in kinetic energy = 0.68×10−197.83×10−19×100

=8.68%