The dissociation energy of h2 is 482.5kj/mol if h2 is exposed to radiant energy of wavelength 124nm , what % of radiant energy
Answers
Answer:
87.15 %.
Explanation:
We know that the bond dissociation energy, which is known as the H-H bond energy which is required for breaking the H2 molecule into hydrogen atoms.
We know the formulae of radiant energy which is :-
hc/λ=6.626×10^−34×3×10^8/124×10^−9 m= 1.6×10^−18.
Hence, radiant energy per mol will be 1.6×10^−18 x 6.022 x 10^23 mol-1 =965365.4 J mol-1 .
In kilo joule we will get radiant energy per mol = 965.36 KJ mol-1.
Again, we know that K.E. is the Radiant energy - Dissociation energy .
= 965.36 - 124 .
= 841.36 KJ mol-1 .
So, the percentage of the radiant energy converted will be K.E. is = 841.36/965.36×100 which on calculating we will get the value of radiant energy as 87.15 %.
Answer:
hii
your answer is here !
Explanation:
We know that the bond dissociation energy, which is known as the H-H bond energy which is required for breaking the H2 molecule into hydrogen atoms.
We know the formulae of radiant energy which is :-
hc/λ=6.626×10^−34×3×10^8/124×10^−9 m= 1.6×10^−18.
Hence, radiant energy per mol will be 1.6×10^−18 x 6.022 x 10^23 mol-1 =965365.4 J mol-1
.
In kilo joule we will get radiant energy per mol = 965.36 KJ mol-1.
Again, we know that K.E. is the Radiant energy - Dissociation energy
.
= 965.36 - 124
.
= 841.36 KJ mol-1
.
So, the percentage of the radiant energy converted will be K.E. is = 841.36/965.36×100 which on calculating we will get the value of radiant energy as 87.15 %.
follow me !