The dissociation equilibrium of a gas AB₂ can be represented
as :
2AB₂ (g) ⇋ 2AB(g) + B₂ (g)
The degree of dissociation is ‘x’ and is small compared to 1.
The expression relating the degree of dissociation (x) with
equilibrium constant Kₚ and total pressure P is :
(a) (2Kₚ/P) (b) (2Kₚ/P)¹/³
(c) (2Kₚ/P)¹/² (d) (Kₚ/P)
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Answer:
a is the answer....
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Hello Friend ..!!
The answer of ur question is..!!
Option.A
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