Question

The dissociation equilibrium of a gas AB₂ can be represented as : $2AB_2(g) \rightleftharpoons 2AB(g) + B_2(g)$ The degree of dissociation is ‘x’ and is small compared to 1. The expression relating the degree of dissociation (x) with equilibrium constant $K_p$ and total pressure P is :
(a) (2$K_p$/P)
(b) $(2K_p/P)^{1/3}$
(c) $(2K_p/P)^{1/2}$
(d) ($K_p$/P)

Answer 1

(A)(2$K_p$/P)