The dissociation of CO, can be expressed as 200, = 200 + O2. If 2 mol of CO, is
taken initially and 40% of the CO, is dissociated completely. What is the total
number of moles at equilibrium:-
(1) 2.4
(2) 2.0
(3) 1.2
(4) 5
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It is given that 2α=2×401002α=2×40100
⇒α=0.4
⇒α=0.4
So total moles at equilibrium = 2−2α+2α+α2−2α+2α+α
==2+α2+0.42.4
2+α=2+0.4=2.4
the correct option is (1) 2.4
Hope this answer is helpful for you.
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