The dissociation of CO2 can be expressed as
2Co <=> 2Co +O2 . lf the 2 mol of CO2 is taken
initially and 40% of the CO2 is dissociated
completely. What is the total number of moles at
equilibrium:-
(1) 2.4 (2) 2.0 (3) 1.2 (4) 5
Answers
Answer:
option 1 is correct
Explanation:
2CO2 ------> 2CO + O2
Initial moles of CO2 are two
Initial moles of CO and O2 are zero
At equilibrium degree of dissociation a = 40%=0.4
for the given reaction
equilibrium moles of CO2 = 2—2a = 2—2(0.4)= 1.2
equilibrium moles of CO = 2a = 2(0.4)= 0.8
equilibrium moles of O2 = a = 0.4
therefore total moles at equilibrium are
1.6+0.8+0.4=2.8
Answer:
2.4 moles
Explanation:
Number of moles dissociated= 40%×initial no. of moles
= (40/100)×2
=0.8
2CO₂ ⇄ 2CO + O₂
@ t=0 2 0 0
@ t=t 2-2x 2x x
no. of moles dissociated = 2x= 0.8⇒ x=0.4
total no. of moles at equilibrium= (2-2x)+ (2x) + x
= 2-0.8 + 0.8 + 0.4
= 2.4 moles