The dissociation of CO2 can be expressed as 2CO2 à 2CO + O2. If the 2 mol of CO2 is taken initially and 40+ of the CO2 is dissociatated completely. What is the total number of moles at equilibrium
Answers
2CO₂ → 2CO + O₂
If we begin with 2 moles of CO₂, and if all of the CO₂ is dissociated at equilibrium, 2 moles of CO and 1 mole of O₂ must have been produced. Hence, the total number of moles at equilibrium would be 2+1 = 3.
The question is technically wrong though. If the entire CO₂ vanishes at equilibrium, there won't be any product concentration left, and hence reaction would cease to occur in the forward direction, while at equilibrium, reaction keeps on taking place in both the forward as well as the backward direction.
Answer:
Explanation:
2CO₂ → 2CO + O₂
If we begin with 2 moles of CO₂, and if all of the CO₂ is dissociated at equilibrium, 2 moles of CO and 1 mole of O₂ must have been produced. Hence, the total number of moles at equilibrium would be 2+1 = 3.
The question is technically wrong though. If the entire CO₂ vanishes at equilibrium, there won't be any product concentration left, and hence reaction would cease to occur in the forward direction, while at equilibrium, reaction keeps on taking place in both the forward as well as the backward direction.