The dissolution of al(oh)3 by a solution of naoh results in the formation of
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Na[Al(H2O)2(OH)4] is the complex molecule which is formed.
Explanation:
- The aluminium is actually an amphoteric element.
- This element can react with both acid and base to form salt.
- The aluminium reacts with bases to from the complex ions.
- Al(OH)3 + NaOH = Na[Al(OH)4].
- But the coordination number of aluminium is generally 6.
- So the rest 2 of the coordinators are fulfilled by water.
- This forms Na[Al(H2O)2(OH)4].
- So the full reaction is
- Al(OH)3 + NaOH + 2H2O = Na[Al(H2O)2(OH)4]
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