Question

the dist of a chord 8cm long from the centre of a circle of radius 5cm a.4cm b.3cm c.2cm d.9cm​

Answer 1

Answer:

Step-by-step explanation:

Apply pythagoras theorem where a right angled triangle is formed when radius bisects chord so Hypotenuse is radius which intersects chord at circumference and side 1 is distance of chord from center

Therefore

distance of chord^2= R^2-S1^2

=5^2-4^2

=25-16

distance = root of 9

= 3 cm

Answer 2

Answer:

hope it may help you