Math, asked by subbu5026, 3 months ago

The distance around a rectangular field is 400 meters. The length of the field is 26 meters
more than the breadth. Calculate the length and breadth of the field?
The length of a rector​

Answers

Answered by fawzan1207
1
Let the breadth of the field is equal to x
Therefore, length is equal to x + 26 m
Perimeter of rectangle = 400
=2((x+26) + x)
=2(2x+26) => 4x+52=>x=-52/4 => -13
=x=-13=breadth
=x+26=13
Answered by ADARSHBrainly
12

{\large{\underline{\underline{\bf{Question :}}}}}

The distance around a rectangular field is 400 meters. The length of the field is 26 meters more than the breadth. Calculate the length and breadth of the field?

{\large{\underline{\underline{\bf{Answer :}}}}}

{\underline{\underline{ \text{\sf{Concept of the question :}}}}}

Here Question is asked from Areas and Perimeter of 2 Dimensional shapes. We have given that Distance around means Perimeter of the rectangular field is 400 meters also length is 26 meters more than the breadth. We need to find both length and Breadth.

{\underline{\underline{{\sf{Assumption : }}}}}

  • Let x be the length of the Rectangular Field and
  • breadth be also the x .

{\underline{\underline{{\sf{Given : }}}}}

  • Perimeter = 400 m
  • Length = x + 26 m
  • Breadth = x

{\underline{\underline{{\sf{To  \:  \: find  : }}}}}

  • At first value of x then
  • Length and breadth of the field.

{\underline{\underline{ \text{\sf{Formula that will be applied   : }}}}}

  • Perimeter of Rectance = 2( length + breadth )

{\underline{\underline{{\sf{Solution  : }}}}}

Substituting the values of length and breadth on formula , we get

{\bf{\implies{Perimeter =2 (l + b ) }}}

{\sf{\implies{400=2 (x + 26+ x ) }}}

{\sf{\implies{ \cfrac{ 400}{2}= (2x+ 26 ) }}}

{\sf{\implies{ 200= 2x+ 26 }}}

{\sf{\implies{ 200 - 26= 2x }}}

{\sf{\implies{ 174= 2x }}}

{\sf{\implies{ x= \cfrac{174}{2} }}}

{ \large{ \boxed{\bf{\implies{x = 87 }}}}}

_____________________________________

Length is

{\bf{\longmapsto{x + 26}}}

{\bf{\longmapsto{87 + 26}}}

  \large{ \underline{ \overline{ \boxed{\bf{\longmapsto{113 \: m}}}}}}

Breadth is

{\bf{\longmapsto{x}}}

\large{ \underline{ \overline{ \boxed{\bf{\longmapsto{87 \: m}}}}}}

So, Length and the Breadth of the rectangle is 113 m and 87 m respectively.

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