The distance between 1st node and 5th antinode of a stationary wave is 9cm. Then wavelength of the wave in cm is
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Answer:
The distance between two adjacent nodes or two adjacent antinodes is equal to half of the wavelength (Figure 5).

therefore the distance between consecutive node and anti-node will be
1/4th of the wavelength.
The distance between a node and the next antinode in a stationary wave is 5cm.
therefore the wavelength = 4 x 5 cm = 20 cm.
Answered by
1
Answer :
The distance between a node and the next antinode in a stationary wave is 5cm. therefore the wavelength = 4 x 5 cm = 20 cm.
Explanation:
distance between one adjacent crest and trough is λ/2 but the distance between one node to its adjacent antinode is λ/4.So according to the question we can say that the distance is λ/4 =5, which is λ=5×4=20
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