The distance between 2 station is 425km .Two trains start simultaneously from these station on parallel tracks to cross each other. The speed of one train is greater than the other by 5km per hour . If the distance between the 2 trains after 3 hrs of their start is 20 km
FIND THE SPEED OF EACH TRAIN.
EXPLAIN IT CLEARLY AND CLEVERLY
Answers
Answered by
12
Let the speed of one train be v km/h
then the speed of another train will be (v+5) km/h
after 3 hours, distance traveled by both trains
3v +3 (v+5) = 425- 20
⇒6v = 390
⇒v = 65 km/h
speed of another train = 65+5 = 70 km/h
then the speed of another train will be (v+5) km/h
after 3 hours, distance traveled by both trains
3v +3 (v+5) = 425- 20
⇒6v = 390
⇒v = 65 km/h
speed of another train = 65+5 = 70 km/h
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Answered by
10
Let the speed of first train be v km/hr
So, speed of another train = (v +5) km/hr
Speed = Distance/Time
v = Distance/3
Distance covered by first train = 3v
Similarly, distance covered by second train = 3(v +5)
So, Distance traveled by first train + Distance travelled by second train + Distance b/w them = Length of track
3v + 3(v +5) + 20 = 425
6v + 35 = 425
6v = 425 - 35
6v = 190
v = 65 km/hr
So, speed of other train = v + 5 = 65 + 5 = 70 km/hr
So, speed of another train = (v +5) km/hr
Speed = Distance/Time
v = Distance/3
Distance covered by first train = 3v
Similarly, distance covered by second train = 3(v +5)
So, Distance traveled by first train + Distance travelled by second train + Distance b/w them = Length of track
3v + 3(v +5) + 20 = 425
6v + 35 = 425
6v = 425 - 35
6v = 190
v = 65 km/hr
So, speed of other train = v + 5 = 65 + 5 = 70 km/hr
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is greater than the other by 5 km per hour.
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