Question

The Distance Between (3,-2) and (K,4 ) Is root37 .... Find Out The Value Of K ...

This Is Containing 40 Points​

Answer 1

A (3,-2) , B (K,4)

DISTANCE (AB)

=

$\sqrt{(k - 3)^{2} + (4 + 2) ^{2} } = \sqrt{37} \\ {k}^{2} + 9 - 6k + 36 = 37 \: \: \: \: (squaring \: both \: sids\\ {k}^{2} - 6k + 45 = 37 \\ {k}^{2} - 6k + 8 = 0 \\ {k }^{2} - 4k - 2k + 8 = 0 \\ (k - 4)(k - 2) = 0 \\ k = 4 \: and \: k = 2$

HOPE IT HELPS YOU

Answer 2

Answer:

=> √(k-3)²+(4+2)² = √37

=> k²-6k +45 = 37

=> k² - 6k + 8 = 0

=> (k-4)(k-2)=0

=> k=2,4