Question

the distance between (-5,7) and (-1,3) is given by​

Answer 1

by distance formula we get

AB=✓(x2-x1)^2+(y2-y1)^2

=✓(-1+5)^2+(3-7)^2

=✓16+25

= ✓41unit

therefore distance of ab is √41 unit

Answer 2

$\sqrt({x2 - x1} ) {}^{2} + (y2 - y1) {}^{2}$

$\sqrt{ ( - 1 + 5) { }^{2} } + \sqrt{(3 - 7) {}^{2} }$

$\sqrt{(4) {}^{2} } + \sqrt{(4) { }^{2} }$

$\sqrt{16 + 16 }$

$\sqrt{32}$

$4 \sqrt{2}$