the distance between 6 m and 11 m poles is 12m then the distance between top edges of poles isthe distance between
Answers
Answer:
hey here is your solution
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pls refer the reference diagram uploaded above
Step-by-step explanation:
so here BM and CD are two poles of heights 11 m and 6 m respectively
thus then BM perpendicular to CB and CD is perpendicular to CB
so angle ABC=angle DCB=90
similarly as angle A and D lies on straight line
angle BAD=angle CDA=90
so in quadrilateral ABCD as all angles are of 90 degrees each
quadrilateral ABCD is a rectangle
hence AB=CD=6 m
BC=AD=12 m
so here BM=AM+AB
ie 11=AM+6
so AM=5 m
so here angle BAD and angle MAD forms a linear pair axiom
thus then angle MAD=90
so applying pythagoras theorem on triangle MAD
we get
MD square=AM.square+AD.square
=(12)square+(5)square
=144+25
=169
taking square roots on both sides we get
MD=13 cm
hence the distance between top edges of poles is 13 cm.
Answer:
refer to the attachment