Question

the distance between a and b is 192.Two people x and y are travelling in two different cars, y takes 2 hours more than x. Determine the average speed of x if speed of y is 16 km/h less than x.

Answer 1

Step-by-step explanation:

let the speed of y be p km/hr

and therefore the speed of x= p+16 km/hr

distance=192km

time=distance/speed

time taken by Y=192/p

time taken by X=192/p+16

according to given condition

192/p - 192/p+16=2

192(1/p -1/p+16)=2

(p-p+16)/p²+16p=2/192

+16/p²+16p=1/96

p²+16p=96*16

p²+16p-1536=0

p²+48p-32p-1536=0

p(p+48)-32(p+48)=0

(p-32)(p+48)=0

p-32=0. or. p+48=0

p=32. or p=-48

speed can't be negative

p≠-48

p=32

speed of y is 32km/hr

and speed of x is 32+16=48km/hr

hope it helps you

please mark it BRAINLIEST