the distance between a line 5x+12y_7=0and5x+12y+45=0
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as they are parallel lines they differ only by constants distance=mod(c1-c2) /root of a^2+b^2
c1 and c2 are constants
mod(7-45)=mod(-36)=36
a=5,b=12
a^2+b^2=5^2+12^2
=25+144=169
root of 169=13
distance=36/13
=3
answer is 3
c1 and c2 are constants
mod(7-45)=mod(-36)=36
a=5,b=12
a^2+b^2=5^2+12^2
=25+144=169
root of 169=13
distance=36/13
=3
answer is 3
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