Question

the distance between a point (0,2)and (0.7)​

Answer 1

According to the question we use distance formula

let us take (0,2) as (x2-x1)

and (0,7) as (y2-y1)

d=√(x2-x1)^2+(y2-y1)^2

d=√(x2-x1)^2+(y2-y1)^2d=√(0-0)^2+(7-2)^2

d=√(x2-x1)^2+(y2-y1)^2d=√(0-0)^2+(7-2)^2d=√(5)^2

d=√(x2-x1)^2+(y2-y1)^2d=√(0-0)^2+(7-2)^2d=√(5)^2d=√25

d=√(x2-x1)^2+(y2-y1)^2d=√(0-0)^2+(7-2)^2d=√(5)^2d=√25d=5