The distance between akola and bhusawal is 168 km. An express train takes 1 hour less than a passenger train to cover the distance. Find the average speed of each train if the average speed of the express train is more by 14 km/hr than the speed of the passenger train
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Solution:
Let the speed of passenger train is x kmph
and that of express train is y kmph
Distance = 168 km
Time taken by Express train to travel between akola to bhusawal = 168/y hour
Time taken by passenger train to travel between akola to bhusawal = 168/x hour
According to the question Express train taking 1 hour less
ATQ
Substitute from eq 2
negative value can be discarded.
Thus Speed of passenger train 42 kmph
Speed of express train = 42+14= 56 kmph
Hope it helps you.
Let the speed of passenger train is x kmph
and that of express train is y kmph
Distance = 168 km
Time taken by Express train to travel between akola to bhusawal = 168/y hour
Time taken by passenger train to travel between akola to bhusawal = 168/x hour
According to the question Express train taking 1 hour less
ATQ
Substitute from eq 2
negative value can be discarded.
Thus Speed of passenger train 42 kmph
Speed of express train = 42+14= 56 kmph
Hope it helps you.
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