Question

the distance between Akola and Bhusawal is 168 km an Express train takes 1 hour less than a passenger train to convert the distance find the average speed of each train is average speed of Express train is more by 14 km per hour than speed of passenger train

Answer 1

Answer:

Speed of passenger train = 42 km/Hr

Speed of express train =   56 km/Hr

Step-by-step explanation:

the distance between Akola and Bhusawal = 168 km

Let say average speed of passenger train  = P km/Hr

average speed of express train = P + 14  km/Hr

Time taken by Passenger Train = $\frac {168}{P}$  Hr

Time taken by Express Train = $\frac {168}{(P+14)}$  Hr

Express train takes 1 hour less than a passenger train

$\frac {168}{P}$   -  $\frac {168}{(P+14)}$   = 1

Multiplying both sides by P(P+14)

168 (P +14) - 168P = P(P+14)

168 × 14 = P² + 14P

P² + 14P - 2352 = 0

P² + 56P - 42P - 2352 = 0

P (P+56) -42(P+56) = 0

(P-42)(P+56) = 0

P = 42 km/Hr   ( P = -56 not possible as speed can not be negative)

Speed of passenger train = 42 km/Hr

Speed of express train = 42 + 14 = 56 km/Hr

Answer 2

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