The distance between an octahedral and tetrahedral void in fcc lattice would be
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Answer:
The distance between any two successive (adjacent) tetrahedral voids. To calculate it, draw a line joining a tetrahedral void to the corresponding vertex. We know that this distance is 3√a43a4, now take the projection of this on any of the edges. The angle between body diagonal and an edge is cos inverse of 13√13, so the projection of the line on an edge is a/4a/4, Similarly the other tetrahedral void will also be a/4a/4 away from its vertex on this edge. So the distance between these two is a−a/4−a/4=a/2
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Answer:
√3 a/4
Explanation:
distance will be body diagonal /4
=(a√3)/4
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