Question

the distance between cities a and b is 290 km . two motorcyclists start simultaneously for a and b in opposite directions and the distance between them after 3 hours is 20 km. if the speed of one motorcyclist is less than that of the other by 10 km/h , find the speed of steamer in still water.​

Answer 1

Speed of first cyclist = X km/hr

speed of other cyclist = (X - 10) km/hr

Distance covered by first cyclist after 3 hours = 3X km

Distance covered by other cyclist after 3 hours = 3(X - 10) km

= (3X - 30) km

ATQ,

3X + 3X - 30 + 20 = 230

6X -10 = 230

6X = 230 + 10

6X = 240

X = 240/6

X = 40

Speed of first cyclist = X

= 40 km

Speed of other cyclist = X - 10

= 40 - 10

= 30 km

@WildCat7083