the distance between cities a and b is 290 km . two motorcyclists start simultaneously for a and b in opposite directions and the distance between them after 3 hours is 20 km. if the speed of one motorcyclist is less than that of the other by 10 km/h , find the speed of steamer in still water.
Answer is 40 km/h ; 50 km / h slove in pross
Answers
Answered by
3
Speed of first cyclist = X km/hr
speed of other cyclist = (X - 10) km/hr
distance covered by first cyclist
after 3 hours = 3X km
distance covered by other cyclist
after 3 hours = 3(X - 10) km
= (3X - 30) km
according to condition,
3X + 3X - 30 + 20 = 230
6X -10 = 230
6X = 230 + 10
6X = 240
X = 240/6
X = 40
therefore,
speed of first cyclist = X
= 40 km
speed of other cyclist = X - 10
= 40 - 10
= 30 km
Answered by
1
Please see the upper answer
mere baski ni hi itna bara answer likhna
Mere to dekhkar hi pasine chuth ghy
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