Question

the distance between(cos0,sin0),(sin0,Cos0) is​

Answer 1

Answer:

Since, cos0=1 and Sin0=0

Therefor, for (cos0,Sin0)=(1,0) and (Sin0,Cos0)=(0,1)

hence the distance between these two points is

= ✓(0-1)^2+(1-0)^2

=✓1+1

=✓2