The distance between Del and Agra is 200km.A train travels the first 100km at a speed of 50km/h.How fast must the train travel the next 100km,so as to average 70km/h for the whole journey?
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Answered by
1
*(50+x)/2=70
*50+x=70*2
*50+x=140
*x=140-50
*x=90
hence next 100 km must travel at 90 km/h to get avg of 70km/m
*50+x=70*2
*50+x=140
*x=140-50
*x=90
hence next 100 km must travel at 90 km/h to get avg of 70km/m
Answered by
2
total distance 200 km
a to q = distance of 100 km is covered in 50km/h
time = 100/ 50 = 2 hour
since 200 km has a speed of 70km/h
time=2 hour approx
and therefore we'll divide 70 by 2 = 35km/h
1st hour = 50km/h
2nd hour = 35*2 = 70km/h - 50km/hr = 20km/hr
speed of train is 20km/hour
a to q = distance of 100 km is covered in 50km/h
time = 100/ 50 = 2 hour
since 200 km has a speed of 70km/h
time=2 hour approx
and therefore we'll divide 70 by 2 = 35km/h
1st hour = 50km/h
2nd hour = 35*2 = 70km/h - 50km/hr = 20km/hr
speed of train is 20km/hour
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