Math, asked by satindersingh1p94hqn, 7 months ago

The distance between Delhi and Agra is 233 km. A car P started travelling from Delhi to Agra

and another car Q started from Agra to Delhi along the same road 1 hour after the car P

started. The two cars crossed each other 75 minutes after the car Q started. Both cars were

travelling at constant speed. The speed of car P was 10 km/hr more than the speed of car Q.

How many kilometres the car Q had travelling when the cars crossed each other?

a. 66.6 b. 88.2 c. 116.5 d. 75.2

Answers

Answered by RvChaudharY50

Given :-

To Find :-

Solution :-

Let us Assume that, speed of car P is x km/h .

Than, speed of car Q will be (x - 10) km/h .

Now, for the first hour car P alone travel . So, it will cover x km distance in one hour.

Than,

→ Distance left to be covered = (233 - x) km.

Now, Q also started from Agra at a speed of (x - 10)km/h.

As, both Travel in opposite direction ,

→ usual speed = Speed of P + Speed of Q

→ usual speed = x + (x - 10) = (2x - 10) km/h.

and,

→ Distance to be covered = (233 - x) km.

Therefore,

→ They will meet after = (Distance Left) / (Usual speed)

Now, meeting time is given 75 minutes after the car Q started.

Hence,

→ (233 - x) / (2x - 10) = 75 minutes

→ (233 - x) / (2x - 10) = (75/60) Hours.

→ (233 - x) / (2x - 10) = 5/4

→ 5(2x - 10) = 4(233 - x)

→ 10x - 50 = 932 - 4x

→ 10x + 4x = 932 + 50

→ 14x = 982

→ x = 70.14 km/h.

So,

→ Speed of car P = x = 70.14 km/h .

→ Speed of car Q = (x - 10) = 60.14 km/h.

Now, we have given that , Car Q travels for 75 minutes before meeting .

Therefore,

→ Speed of car Q = 60.14 km/h

→ Time = 75 minutes = (5/4) Hours.

→ Distance covered = Speed * Time

→ Distance = 60.14 * (5/4)

→ Distance = 75.2km . (Ans.)

(Nice Question .)

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