Question

The distance between edge plus and cl minus ion in hcl molecule is 1.28 angstrom what will be the potential due to this dipole at a distance of 12 a on the axis of dipole

Answer 1

Answer

0.13 v

Step by Step Explanation

Given The distance between edge plus and cl minus ion in hcl molecule is 1.28 angstrom what will be the potential due to this dipole at a distance of 12 a on the axis of dipole

We know that  

       V = k . p/r^2

Charge of an electron is 1.6 x 10^19.

       V = 9 x 10^9 x (1.6 x 10^-19) x (1.28 x 10^-10) / (12 x 10^- 10)^2

       V = 18.432 / 144

      V = 0.13 V

Answer 2

Answer:

Explanation:

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