Question

The distance between electron and proton in a hydrogen atom is 5.3 X 10-11 meter.
Calculate the electric attractive force between them. Compare this force with the
Gravitational force (G=6.67 X 10-11)
Charge of electron (e = 1.6 X 10-19 C)
Mass of electron me = 9.1 X 10-31 kg
Mass of proton mp = 1.67 X 10-27 kg​

Answer 1

Answer:

Explanation:HIIIII

Answer 2

Explanation:

q1=q2=1.6×10^-19C

k=9×10^9

r=5.3×10^-11

F=?

F=k.q1.q2/r^2

F=9×10^9×1.6×10^-19×1.6×10^-19/(5.3×10^-11)^2

F=0.82×10^-7 N