The distance between H+ and Cl- ions in HCl molecule is 1.38A. Find out the electric dipole moment of HCl.
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Answer:
Here 2a=1.38×10−10m,r=10×10−10mq=1.6×10−19C, θ=0∘
As potential,
V=4πε0r2P cosθ
=4πε0r2q(2a)
=(10×10−10)29×109×1.6×10−19×1.38×10−10
V=0.2V
Explanation:
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