Question

The distance between Hand C1 ions in HCI molecules is 1.38 Aº. The potential due to this dipole at a distance of 10 Aº on the axis of dipole is​

Answer 1

Answer:

Here 2a=1.38×10

−10

m,r=10×10

−10

mq=1.6×10

−19

C, θ=0

∘

As potential,

V=

4πε

0

r

2

P cosθ

=

4πε

0

r

2

q(2a)

=

(10×10

−10

)

2

9×10

9

×1.6×10

−19

×1.38×10

−10

V=0.2V