Question

The distance between kanpur & jaipur is 90 km.A started from jaipur with 5 kmph and b started from kanpur with 3 kmph.B increases his speed 1.5every hour.When will they meet?

Answer 1

Answer:

Given:

Speed of:

$\implies$ A = 5 km/hr

$\implies$ B = 3 km/hr

Acceleration of:

$\implies$ B = 1.5 km/hr²

$\implies$ A = 0

Now: $\boxed{\sf{S_{A} + S_{B}=90}}$

So we get:

$\implies$ $\sf{5t + 3t + \frac{1}{2} \times 1.5 \times t^{2} = 90}$

That is:

$\implies$ $\sf{8t + 0.75= 90}$

$\implies$ $\sf{0.75t^{2} + 8t - 90 = 0}$

On solving this quadratic equation we get:

t = 6.85 sec

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Answered by: Niki Swar, Goa❤️

Answer 2

Answer:

$30 \\ 18$

Step-by-step explanation:

because90/3=30 and

90/5=18