The distance between layers in a NaCl crystal is 282 pm. X-rays are diffracted from these layers at an angle of 23.0o. Assuming that n = 1, calculate the wavelength of the X-rays in nm.
Answers
Given info : The distance between layers in a NaCl crystal is 282 pm. X-rays are diffracted from these layers at an angle of 23.0o. Assuming that n = 1.
To find : the wavelength of the X - ray in nm.
Solution : using Bragg's law of x - ray diffraction, nλ = 2dsinθ
Distance between layers of NaCl, d = 282 pm θ = 23° , n = 1
So, 1 × λ = 2 × 282sin23°
λ = 220.4 pm = 0.2204 nm
Therefore the wavelength of the X rays is 0.2204 nm
Answer:
Given info : The distance between layers in a NaCl crystal is 282 pm. X-rays are diffracted from these layers at an angle of 23.0o. Assuming that n = 1.
To find : the wavelength of the X - ray in nm.
Solution : using Bragg's law of x - ray diffraction, nλ = 2dsinθ
Distance between layers of NaCl, d = 282 pm θ = 23° , n = 1
So, 1 × λ = 2 × 282sin23°
λ = 220.4 pm = 0.2204 nm
Therefore the wavelength of the X rays is 0.2204 nm