Question

The distance between Na and cl ion in nacl is 1.28 angstrom. Calculate the electric dipole moment of the molecule

Answer 1

Explanation:

The distance between edge plus and cl minus ion in hcl molecule is 1.28 angstrom what will be the potential due to this dipole at a distance of 12 a on the axis of dipole

Answer0.13 vStep by Step ExplanationGiven The distance between edge plus and cl minus ion in hcl molecule is 1.28 angstrom what will be the potential due to this dipole at a distance of 12 a on the axis of dipole We know that V = k . p/r^2 Charge of an electron is 1.6 x 10^19. V = 9 x 10^9 x (1.6 x 10^-19) x (1.28 x 10^-10) / (12 x 10^- 10)^2 V = 18.432 / 144 V = 0.13 V