The distance between origin and the point x-axis is _______
Guyz pla answer this ill mark as brainlist..
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Let the point be P
P = (x2 + x1)/2 , (y2 + y1)/2
Ramanan2018:
Sorry it’s a wrong answer...
Tq..
I couldn’t complete it
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Coordinates of origin (0,0)
Distance = √(x2-0) + (y2 - 0)
= √x2 + y2
Distance = √(x2-0) + (y2 - 0)
= √x2 + y2
Oki tq
Answered by
1
x-axis coordinate = (x, 0)
origian= (0,0)
distance formula = √(x2-x1)^2+(y2-y1)^2
=√(x-0)^2-(0-0)^2
= √x^2
= x
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