Question

The distance between P=(2 sinA,0) and Q=(0,2 cosA)​

Answer 1

Answer:

these two have a distance of 4words

Answer 2

given that

p=(2 sinA,0), and Q=(0,2cosA)

the distance between p and Q =

PQ=√ (X2-X1 )^2 +(Y2-Y1)^2

PQ=√(0-2sinA)^2+(2cosA-0)^2

PQ=√(-2sinA)^2+(2cosA)^2

PQ=√4sinA^2+4cosA^2

PQ=√4(sinA^2+cosA^2)

PQ=√4(1)

PQ=2