Question

the distance between points (cos thita, - sin thita) and (sin thita, cos thita)​

Answer 1

Answer:

like picture you can solve the problem

Answer 2

Answer:

√2

Step-by-step explanation:

(cosθ , - sinθ)    (sinθ , cosθ)

Using Distance formula,

√(x₂ - x₁)² + (y₂ - y₁)²

√(sinθ - cosθ)² + (cosθ - (-sinθ))²

√(sinθ - cosθ)² + (cosθ + sinθ)²             ∵ {(a + b)² = a² + b² + 2ab}

√[(sin²θ + cos²θ) - 2sinθcosθ + (cos²θ + sin²θ) + 2sinθcosθ]

√(sin²θ + cos²θ) + (cos²θ + sin²θ)

√1 + 1

√2

* {sin²θ + cos²θ = 1}