Question

the distance between rams native place and his friend shamz native place is 120 km they started simultaneously moving towards each other the meet after 10 hours if RAM speed is decreased by third and shams doubles his speed then also they will meet again after 10 hours what is the speed of RAM in kilometre per hour

Answer 1

Answer:
Speed of Ram is 9 kmph
and speed of shyam is 3 kmph

Solution:

Let the speed of Ram is x kmph

and speed of shyam is y kmph

Distance travel by Ram in 10 hours=10x

Distance travel by Shyam in 10 hours= 10y

Since the distance travel by both is 120 km

So

$10x + 10y = 120 \\ \\ x + y = 12....eq1$
if RAM speed is decreased by three ,so now speed of Ram is (x-3) kmph

and shams doubles his speed then speed of Shyam is 2y kmph,also they will meet again after 10 hours

Distance travel by Ram in 10 hours=10(x-3)

Distance travel by Shyam in 10 hours= 10(2y)

Since the distance travel by both is 120 km

$10(x-3)+ 20y = 120 \\ \\ 10x+20y-30 = 120 \\ \\ 10x + 20y = 150 \\ \\ x + 2y = 15...eq2$
Subtract both equations

$x + y = 12 \\ x + 2y = 15 \\ - \: \: \: - \: \: \: \: \: - \\ - - - - - - \\ y= 3 \\ \\ x + 3 = 12 \\ \\ x = 12 -3 \\ \\ x =9$
Speed of Ram is 9 kmph

and speed of shyam is 3 kmph

Answer 2

Answer:

9 & 3 km/hr Original speeds

Step-by-step explanation:

Let say Speed of Ram = 3R km/Hr

Speed of Shamz = S km/Hr

Distance covered in 10 hrs = 10 * 3R  + 10S  = 120

=> 3R + S = 12   - eq 1

RAM speed is decreased by third  

=> Ram new speed = 3R - (3R/3) = 2R km/Hr

shams doubles his speed  = 2S km /Hr

=> 10 * 2R  + 10*2S = 120

=> R + S = 6    - eq 2

Eq 1  - Eq 2

=> 2R = 6

=> R = 3

=> S = 3

Speed of Ram = 3R = 9 km/hr

Speed of shamz = 3 km /hr