Math, asked by teddy3012, 1 year ago

the distance between school and metro station is 300 m kartikey starts running from school toward metro station while ashu starts running from metro station to school they meet after 4 minutes has kartikeya doubled his speed and ashu reduced his speed to third of the original they would have met one minute earlier find their speed

Answers

Answered by amitnrw
0

Given : The distance between school and metro station is 300 m . Kartikay starts running from school towards metro station, while Ashu starts running from metro station to school. They meet after 4 minutes.

To find : Find their original  speeds

Solution:

Let Say Ashu Speed  =  3A  m/min

Kartikay Speed   =   K  m/min

They meet after 4 mins

=> 4(3A)  + 4( K)   = 300

=> 3A +  K  = 75

Kartikay doubled his speed = 2K m/s

Ashu  reduced his speed to third of the origina = A m/s

Meet 1 min earlier => 4 - 1 = 3 Mins

=> 3A + 3(2K)  = 300

=>  A + 2K  = 100

6A - A =  50

=> A = 10    => 3A  = 30

=>  K = 45

Ashu Speed  =  30  m/min  

Katikay Speed   =  45  m/min

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