The distance between school and metro station is 300 m. Kartikay starts running from school towards metro station, while Ashu starts running from metro station to school. They meet after 4 minutes. Had Kartikay doubled his speed and Ashu reduced his speed to third of the original they would have met one minute earlier. Find their speeds
Answers
Given : The distance between school and metro station is 300 m . Kartikay starts running from school towards metro station, while Ashu starts running from metro station to school. They meet after 4 minutes.
To find : Find their original speeds
Solution:
Let Say Ashu Speed = 3A m/min
Kartikay Speed = K m/min
They meet after 4 mins
=> 4(3A) + 4( K) = 300
=> 3A + K = 75
Kartikay doubled his speed = 2K m/s
Ashu reduced his speed to third of the origina = A m/s
Meet 1 min earlier => 4 - 1 = 3 Mins
=> 3A + 3(2K) = 300
=> A + 2K = 100
6A - A = 50
=> A = 10 => 3A = 30
=> K = 45
Ashu Speed = 30 m/min
Katikay Speed = 45 m/min
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