Math, asked by serah12313, 1 year ago

The distance between school and metro station is 300 m. Kartikay starts running from school towards metro station, while Ashu starts running from metro station to school. They meet after 4 minutes. Had Kartikay doubled his speed and Ashu reduced his speed to third of the original they would have met one minute earlier. Find their speeds

Answers

Answered by amitnrw
3

Given : The distance between school and metro station is 300 m . Kartikay starts running from school towards metro station, while Ashu starts running from metro station to school. They meet after 4 minutes.

To find : Find their original  speeds

Solution:

Let Say Ashu Speed  =  3A  m/min

Kartikay Speed   =   K  m/min

They meet after 4 mins

=> 4(3A)  + 4( K)   = 300

=> 3A +  K  = 75

Kartikay doubled his speed = 2K m/s

Ashu  reduced his speed to third of the origina = A m/s

Meet 1 min earlier => 4 - 1 = 3 Mins

=> 3A + 3(2K)  = 300

=>  A + 2K  = 100

6A - A =  50

=> A = 10    => 3A  = 30

=>  K = 45

Ashu Speed  =  30  m/min

Katikay Speed   =  45  m/min

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