Question

The distance between the centres of two circles having radius 3cm, 1cm is 8cm, then the
length of their common transverse tangent is in cm​

Answer 1

Step-by-step explanation:

Consider the above figure, the radii of the first circle is AP=3 cm and the radii of the second circle is QB=8 cm.

Now since AP=3, therefore QC=3 and thus BC=QB−QC=8−3=5

We find the length AC as follows:

AC= √13² −5² = √169−25 = √144 =12

Hence, PQ=AC=12 cm.

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