Question

The distance between the genes a,b,c,d in mapping units are a-d=3.5, b-c=1, a-b=6, c-d=1.5,a-c=5.Find out the sequence of arrangements of the gene's

Answer 1

the correct ans is
adcb

Answer 2

Answer:

Step-by-step explanation:

Draw a line and put

A-B =6 in the same line put

A-C =5

So C will come between A and B point in the line

In the same line again

A-D=3.5

So D will come between A and C point in the line

Again

C-D=1.5 or D-C=1.5

B-C=1 or C-B=1

So the arrangement will be ADCB