The distance between the lines 2x+2y+2=0 and
2x+2y+5=0 is
a. 3/2
b. 3√2/2
C.3/2√2
d. 5/2
e. 3
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Answer:
A = 2, B = 2, C1 = 2, C2 = 5
d = | C2-C1 | / √(A²+B²)
= 3 / √8
= 3/2√2units
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