Question

the distance between the lines 3x+4y=9 and 6x+8y+15 is

Answer 1

Answer:

Step-by-step explanation:

distance between two parallel lines ax+by+c1 = 0 & ax+by+c2 = 0

d = |c1-c2|/√(a²+b²)

hence,

d = |9-15/2|/√(3²+4²)

d = |3/2|/5

d = 3/10 

i hope you will understand.