Question

the distance between the objective lens and the eye-peice of an astronomical telescope will be

1)fo/fe
2)fe/fo
3)fo+fe
4)fo-fe

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Answer 1

Answer :

The distance between the objects lens and the eye-piece of an astronomical telescope is $\bf{f_o+f_e}$

• $\sf{f_o}$ denotes focal length of objective lens
• $\sf{f_e}$ denotes focal length of eye-piece

$\dag\:\underline{\boxed{\bf{\orange{Astronomical\:Telescope:}}}}$

» It is an optical instrument used to increase the visual angle of distant large objects such as a star a planet or a cliff etc.

» Astronomical telescope consists of two converging lens. The one facing the object is called adjustable.

» As telescope is used to see distant objects, in it object is between $\infty$ and 2F of objective and hence image formed by objective is real, inverted, and diminished and is between F and 2F on the other side of it.

» The image is acts as object for eye-piece and shifting the position of eye-piece is brought with in its focus. So final image I, with respect to intermediate image is erect, virtual, enlarged and at a distance D to $\infty$ from the eye.

» This in turns implies that final image with respect to object is inverted, enlarged and at a distance D to $\infty$ from the eye.

Answer 2

Answer:

Option 3 is correct

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