Question

the distance between the parallel lines 3x+4y+3=0 and 6x+8y+11=0


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Answer 1

Answer:

distance=1/2 units

Step-by-step explanation:

3x+4+3=0.........(1)

6x+8y+11=0.......(2)

the co-efficient of x and y in both eqns are not equal

therefore, eqn( 2) ÷ 2

then eqn (2) becomes :-3x+4y+11/2 =0

now, distance = |c1-c2|÷√A^2+B^2

c1=3

C2=11/2

A=3

B=4

therefore, d= |3-11/2|÷√3^2+4^2

=|(6-11)÷2| ÷ √9+16

=5/2÷5

=1/2