the distance between the parallel to sides of a trapezium which are in the ratio of 3:5 is 22 cm . if the area of the trapezium is 1100cm², find the parallel sides of the trapezium.
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Answered by
0
Answer:
area of trapezium = height * sum of parallel sides /2
therefore, 1100= 22*5x +3x/2
1100=22*8x/2
1100=22*4x
1100/22=4x
50=4x
50/4=x
12.5 = x
5x = 5*12.5 = 77.5
5x = 5*12.5 = 77.53x = 3*12.5 = 34.5
Answered by
5
ratio of the parallel sides=3:5
so these sides are 3x, 5x
distance between the parallel sides=22cm
Area of the Trapezium =22/2(3x+5x)
=88x
but it is equal to 1100cm^2
88x=1100
x=1100/88
=100/8
=12.5
so parallel sides are
3x=3X12.5=37.5cm
5x=5X12.5=62.5cm
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