the distance between the point (2,3) and (6,6) is
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Distance between the points (2, 3) and (6, 6)
Let (x1, y1) = (2, 3) and (x2, y2)
= (6, 6) d = √((x2 - x1)^2 + (y2 - y1)^2)
= √((6 - 2)^2 + (6 - 3)^2) d
= √(4^2 + 3^2)
= √(16 + 9)
= √(25) =5 units
5 units. Hence, the distance between the points P (2,3) and Q (6,6) is 5 units.
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