Question

the distance between the point 5,2 and 9,2​

Answer 1

Answer:

The answer is 4

Step-by-step explanation:

Formula: Distance between the points $(x_1,y_1)$ and $(x_2,y_2)$ is given by

                                      $\boxed{\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}$

Therefore distance between the points $(5,2)$ and $(9,2)$ is

                                      $=\sqrt{(9-5)^2+(2-2)^2}=\sqrt{4^2+0}=\sqrt{16}=4$

Shortcut: Since the points (5,2) and (9,2) lies in a horizontal line so the distance will be the difference of the abscissas

Answer 2

The distance between point 5,2 and 9,2 is 4 units.

Step-by-step explanation:

Step 1: Given points are (5,2) and (9,2)

formula: distance between two points= $\sqrt{(x1-x2)^{2} +(y1-y2)^{2} }$

here x1=5,x2=9,y1=2,y2=2.

Step 2:

distance=$\sqrt{(9-5)^{2}+ (2-2)^{2} }$

distance=$\sqrt{4^{2} }$

distance=4 units