Question

the distance between the point A(0,6) and B(0,-2) is

6 units

8 units

4units

2 units​

Answer 1

Given :-

• Coordinates of point A = (0,6)
• Coordinates of point B = (0,-2)

To Find :-

• The distance between points A and B.

Solution :-

Distance between two points whose coordinates are (x₁ , y₁) and (x₂ , y₂) is given by ,

$\\ \dag\:{\boxed{\rm{D = \sqrt{(x_2 - x_1) {}^{2} + (y_2 - y_1)^{2} } }}}$

Comparing the coordinates with the formula. We get ,

• x₁ = 0 , y₁ = 6
• x₂ = 0 , y₂ = -2

Substituting the values in the formula ,

$\\ : \implies \sf \: D = \sqrt{(0- 0)^{2} + ( - 2 - 6)^{2} }$

$\\ : \implies \sf \: D = \sqrt{ { ( - 8)}^{2} }$

$\\ : \implies \sf \: D = \sqrt{64}$

$\\ : \implies{\underline{\boxed {\pink{\mathfrak{D = 8 \: units}}}}} \: \bigstar$

Hence ,

• The distance between the points A(0,6) and B(0,-2) is 8 units

Answer 2

To Find:-

• Find distance between point A and B

Given:-

• Point A = ( 0 , 6 )
• Point B = ( 0 , - 2 )

Solution:-

As we know that:-

$\tt\implies \: D = \sqrt{(x_2 - x_1)^{2} + (y_2 - y_1)}^{2}$

$\tt\implies \: D = \sqrt{( 0 - 0 )^{2} \: \: + \: \: ( - 2 \: - 6)^{2}}$

$\tt\implies \: D = \sqrt{ { ( - 8 ) }^{ 2 } }$

$\tt\implies \: D = \sqrt{ 64 }$

$\tt\implies \: D = 8 \: units$

Hence,

• Distance between A and B is 8 units.