the distance between the point A(4,1)&B(1,1) is
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1
Answer:
3
Step-by-step explanation:
since distance between p(x1, y1), q(x2, y2) is
√(x2-x1)^2 + (y2-y1) ^2
= √(1-4)^2 +(1-1)^2
= √(-3)^2 - 0
= √9
+3 or - 3
since distance can't be negative
the answer is 3 units
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